"H_0:a=36400"
"H_1:a>36400"
Test statistic: "T={\\frac {(x-a)*\\sqrt n} {\\sigma}}" , where x - sample mean, a - assumed mean, n - sample size, "\\sigma" - standard deviation
in the given case we have: "T={\\frac {(37900-36400)*\\sqrt {45}} {5600}}=1.797"
Since sample size is big(>30), then it is appropriate to use z-score as critical value, so
"P(Z>Cr)=\\alpha=0.1\\implies Cr=1.282"
Since T>Cr, then we should reject the null hypothesis and conclude that, based on the obtained data, mean is significantly greater than 36400
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