X is a normally distributed random variable with a mean of 60 and standard
deviation of 8. Find the probabilities indicated by using the table.
(a) P(X < 52)
(b) P(48 < X < 64)
(c) P(X > 57)
"(a) P(X < 52)=P(z < \\frac{52-60}{8})\\\\=P(z < -1)=0.5-P(0<z < 1)\\\\=0.5-0.3413=0.1587\n\n\\\\(b) P(48 < X < 64)=P(\\frac{48-60}{8}<z < \\frac{64-60}{8})\\\\=P(-1.5<z < 0.5)\\\\=P(0<z < 0.5)+P(0<z < 1.5)\\\\=0.1915+0.4332=0.6247\n\n\\\\(c) P(X > 57)=P(z > \\frac{57-60}{8})\\\\=P(z >-0.38)=0.5+P(0<z <0.38)\\\\=0.5+0.1480=0.6480"
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