Question

'Bhartdarshan' is an Internet-based travel agency wherein customers can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400.

a. What is the probability of getting more than 12,000 hits ?

b. What is the probability of getting fewer than 9,000 hits ?

Answer 1

$\mu=10000,\sigma=2400$

a)

$P(x>12000)=P(Z>\frac{12000-10000}{2400})$

$=P(Z>0.83)$

$=1-P(Z<0.83)$

$=1-0.79673$

$=0.20327$

b)

$P(X<9000)=P(Z<\frac{9000-10000}{2400})$

$P(Z<-0.42)$

$=0.33724$