Two coins are tossed and the random variable Z gives the number of heads. Find the range space, possible outcomes, and give the table of values.
The range space:HH,HT,TH,TTPossible outcomes:0,1,2P(Z=0)=P(TT)=14P(Z=1)=P(HT)+P(TH)=14+14=12P(Z=2)=P(HH)=14The\,\,range\,\,space: HH,HT,TH,TT\\Possible\,\,outcomes: 0,1,2\\P\left( Z=0 \right) =P\left( TT \right) =\frac{1}{4}\\P\left( Z=1 \right) =P\left( HT \right) +P\left( TH \right) =\frac{1}{4}+\frac{1}{4}=\frac{1}{2}\\P\left( Z=2 \right) =P\left( HH \right) =\frac{1}{4}Therangespace:HH,HT,TH,TTPossibleoutcomes:0,1,2P(Z=0)=P(TT)=41P(Z=1)=P(HT)+P(TH)=41+41=21P(Z=2)=P(HH)=41
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