μ(3,4,5)=(3+4+5)/3=4
μ(3,4,6)=(3+4+6)/3=4.3
μ(3,4,7)=(3+4+7)/3=4.7
μ(3,4,8)=(3+4+8)/3=5
μ(3,4,9)=(3+4+9)/3=5.3
μ(4,5,6)=(4+5+6)/3=5
μ(4,5,7)=(4+5+7)/3=5.3
μ(4,5,8)=(4+5+8)/3=5.7
μ(4,5,9)=(4+5+9)/3=6
μ(5,6,7)=(5+6+7)/3=6
μ(5,6,8)=(5+6+8)/3=6.3
μ(5,6,9)=(5+6+9)/3=6.7
μ(6,7,8)=(6+7+8)/3=7
μ(6,7,9)=(6+7+9)/3=7.3
μ(7,8,9)=(7+8+9)/3=8
Total 15 cases
Histogram has form of integer distribution.
f(4)=f(4.3)=f(4.7)=f(5.7)=f(6.3)=f(6.7)=f(7)=f(7.3)=f(8)=1/15
f(5)=f(5.3)=f(6)=2/15
E(x)=∑fx=2/15(4+4.3+4.7+5.7+6.3+6.7+7+7.3+8)+2/15(5+5.3+6)=3.6+2.2=5.8
σ2=∑fx2−(∑fx)2=1/15(16+18.48+22.09+32.49+39.69+44.89+49+53.29+64)+2/15(25+28.09+36)−33.64=22.66+11.88−33.64=0.93
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