Question #318234

In a population of adults ages 18 to 65, BMI (body mass index) is normally distributed with a mean of 27 and a standard deviation of 5.

a. What is the BMI score for which half of the population has a lower value?

b. What BMI marks the bottom 25% of the distribution for this population?

c. What BMI marks the bottom 5% of the distribution for this population?

d. What BMI value marks the upper 10% of the distribution for this population?

e. What BMI value marks the upper 30% of the distribution for this population?





1
Expert's answer
2022-03-28T10:55:49-0400

a.P(x<z)=0.5

Z=0

X=zσ+μ=0×5+27=27X=z \sigma +\mu=0\times 5+27=27

b. P(x<z)=0.25

Z=-0.675

X=zσ+μ=0.675×5+27=23.625X=z \sigma +\mu=-0.675\times5+27=23.625

c. P(x<z)=0.05

Z=-1.645

X=zσ+μ=1.645×5+27=18.775X=z \sigma +\mu=-1.645\times5+27=18.775

d. P(x>z)=1-P(x<z)=1-0.1=0.9

Z=1.185

X=zσ+μ=1.185×5+27=32.925X=z \sigma +\mu=1.185\times5+27=32.925

e.P(x>z)=1-P(x<z)=1-0.3=0.7

Z=0.525

X=zσ+μ=0.525×5+27=29.625X=z \sigma +\mu=0.525\times5+27=29.625



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