Question #315695

For a certain type of copper wire, it is known that, on the average, 1.5 flaws occur per


millimeter. Assuming that the number of flaws is a Poisson random variable, what is


the mean number of flaws in a portion of length 5 millimeters? What is the


probability, in 4 significant figures, that no flaws occur in a certain portion of wire of


length 5 millimeters?

1
Expert's answer
2022-03-23T05:07:16-0400

XPoiss(1.5l),llengthinmmX5Poiss(1.55)=Poiss(7.5)EX5=7.5P(X5=0)=e7.5=0.0005531X\sim Poiss\left( 1.5l \right) , l\,\,-\,\,length\,\,in\,\,mm\\X_5\sim Poiss\left( 1.5\cdot 5 \right) =Poiss\left( 7.5 \right) \\EX_5=7.5\\P\left( X_5=0 \right) =e^{-7.5}=0.0005531


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