Find the mean of the probability distribution of a random variable X which if š(š) =
š„+1
20
for X= 1, 2, 3, 4, and 5.
P(X=1)=220P(X=1)={\frac 2 {20}}P(X=1)=202ā
P(X=2)=320P(X=2)={\frac 3 {20}}P(X=2)=203ā
P(X=3)=420P(X=3)={\frac 4 {20}}P(X=3)=204ā
P(X=4)=520P(X=4)={\frac 5 {20}}P(X=4)=205ā
P(X=5)=620P(X=5)={\frac 6 {20}}P(X=5)=206ā
M(W)=220ā1+320ā2+420ā3+520ā4+620ā5=7020=3.5M(W)={\frac 2 {20}}*1+{\frac 3 {20}}*2+{\frac 4 {20}}*3+{\frac 5 {20}}*4+{\frac 6 {20}}*5={\frac {70}{20}}=3.5M(W)=202āā1+203āā2+204āā3+205āā4+206āā5=2070ā=3.5
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!