Question #315660

Find the mean of the probability distribution of a random variable X which if 𝑃(𝑋) =

𝑥+1

20

for X= 1, 2, 3, 4, and 5.


1
Expert's answer
2022-03-24T09:45:41-0400

P(X=1)=220P(X=1)={\frac 2 {20}}

P(X=2)=320P(X=2)={\frac 3 {20}}

P(X=3)=420P(X=3)={\frac 4 {20}}

P(X=4)=520P(X=4)={\frac 5 {20}}

P(X=5)=620P(X=5)={\frac 6 {20}}

M(W)=2201+3202+4203+5204+6205=7020=3.5M(W)={\frac 2 {20}}*1+{\frac 3 {20}}*2+{\frac 4 {20}}*3+{\frac 5 {20}}*4+{\frac 6 {20}}*5={\frac {70}{20}}=3.5

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS