An electronic company in Laguna manufactures resistors that have a mean resistance of 120 ohms and a standard deviation of 13 ohms. Find the probability that a random sample of 40 resistors will have an average resistance greater than 114 ohms.
We have a normal distribution, "\\mu=120, \\sigma=13, n=40."
Let's convert it to the standard normal distribution,
"z=\\cfrac{\\bar{x}-\\mu}{\\sigma\/\\sqrt{n}}" =
"=\\cfrac{114-120}{13\/\\sqrt{40}}=-2.92,"
"P(\\bar{X}>114)=1-P(\\bar{X}<114)=\\\\\n=1-P(Z<-2.92)="
"=1-0.0018=0.9982" (from z-table)
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