Question #311271

Random samples of size 4 are drawn with replacement from a finite population 3,6,9. Find the variance of the sample and the standard deviation of the sample

1
Expert's answer
2022-03-15T03:59:57-0400

We have population values 3,6,93,6,9 population size N=3N=3 and sample size n=4.n=4. Thus, the number of possible samples which can be drawn without replacement is



Nn=34=81N^n=3^4=81



To find variance and standard deviation we should find mean

In sampling with replacement the mean of all sample means equals the mean of the population:



μXˉ=μ=3+6+93=6\mu_{\bar{X}}=\mu=\dfrac{3+6+9}{3}=6


When sampling with replacement the variance of all sample means equals the variance of the population divided by the sample size



σ2=13((36)2+(66)2+(96)2=6\sigma^2=\dfrac{1}{3}((3-6)^2+(6-6)^2+(9-6)^2=6Var(Xˉ)=σXˉ2=σ2n=64=1.5Var(\bar{X})=\sigma_{\bar{X}}^2=\dfrac{\sigma^2}{n}=\dfrac{6}{4}=1.5σXˉ=σXˉ2=σ2n=σn\sigma_{\bar{X}}=\sqrt{\sigma_{\bar{X}}^2}=\sqrt{\dfrac{\sigma^2}{n}}=\dfrac{\sigma}{\sqrt{n}}=64=1.51.224745=\dfrac{\sqrt{6}}{\sqrt{4}}=\sqrt{1.5}\approx1.224745

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