Compute the length of the confidence interval for estimating the population
mean using a sample size of 300 and with a standard deviation 84. Use a 92%
confidence level.
According to the confidence interval formula
"a\\in (x-Cr_{\\alpha}*{\\frac s {\\sqrt n}},x+Cr_{\\alpha}*{\\frac s {\\sqrt n}})" , where a - estimated mean, x - sample mean, "Cr_{\\alpha}" - critical value at alpha confidence level, s - sample standard deviation, n - sample size
Since n is big(>30), then it is appropriate to use z-statistic as critical value, then
"P(Z>Cr)={\\frac {1-{\\alpha}} 2}=0.04\\implies Cr=1.75"
so, "Cr_{\\alpha}*{\\frac s {\\sqrt n}}=1.75*{\\frac {84} {\\sqrt {300}}}=8.487"
Then lenght of the confidence interval is 2*8.487=16.974
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