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A survey on 200 Senior High School learners on how much time they read per
week has a confidence interval of (13.5, 17.9) in hours at 95% confidence level.
What is the margin of error? _________________________
What is the average time they read per week? __________________
Since the confidence interval is symmetric,
The margin of error is "\\frac{17.9-13.5}{2}=2.2"
The average time is "\\frac{13.5+17.9}{2}=15.7"
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