Consider a population consisting of 2,6,8,0 and 1. Suppose samples of size 2 are drawn from this population. Find the Mean and Variance of the sampling distribution of sample means.
Since there are 5 elements and 2 of them are taken to form a sample, then there will be "{5 \\choose 2}=10" samples(without replacement). They are listed below
(2,6); (2,8); (2,0); (2,1); (6,8); (6,0); (6,1); (8,0); (8,1); (0,1)
Sample means: 4, 5, 1, 1.5, 6, 3, 3.5, 4, 4.5, 0.5
Mean of sampling distribution of means: "{\\frac {4+...+0.5} {10}}={\\frac {33} {10}}=3.3"
Variance of sampling distribution of means: "{\\frac {(4-3.3)^2+...+(0.5-3.3)^2} {10}}={\\frac {28.55} {10}}=2.855"
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