The probability of getting a defective bottle from a manufacturer is 0.05. A sample of 10 bottles were selected. Calculate the probability of getting 2 defective bottles.
Solution
Let X represent the defective bottles
"P(X) =0.05"
"X\\backsim B(10,0.05)"
"P(X=2)="
"^{10}C_2(0.95)^{10-2}(0.05)^2"
"P(X=2)=45(0.66342).(0.05^2)"
"P(X=2)=0.0017"
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