Let X be a random variable that is normally distributed with a mean of 10 and a
standard deviation of 2. Assume that a sample of 25 observations are taken from
this distribution, What is the interquartile range of the distribution of the sample
means.
Q1= "\\mu" - (0.675)*"\\frac{\\sigma}{\\sqrt{n}}"
Q3="\\mu" + (0.675)*"\\frac{\\sigma}{\\sqrt{n}}"
Given "\\mu" = 10, "\\sigma" =2 and n=25.
Then,
Q1="10-(0.675)\\frac{2}{\\sqrt{25}}" =9.73
Q3= "10+(0.675)\\frac{2}{\\sqrt{25}}" =10.27
The interquartile range (IQR) = Q3-Q1.
=10.27 - 9.73
=0.54
Answer: 0.54
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