The mean number of houses sold by a real estate agent per week is 2. Find the
probability that over the next 6 weeks, the real-estate agent sells between 5 and
12 houses (both inclusive).
This is a Poisson distribution with μ=2∗6=12.\mu=2*6=12.μ=2∗6=12.
P(5≤X≤12)=e−12(1255!+1266!+1277!+1288!+1299!+121010!+121111!+121212!)=0.5684.P(5\le X\le12)=e^{-12}(\frac{12^5}{5!}+\frac{12^6}{6!}+\frac{12^7}{7!}+\frac{12^8}{8!}+\frac{12^9}{9!}+\frac{12^{10}}{10!}+\frac{12^{11}}{11!}+\frac{12^{12}}{12!})=0.5684.P(5≤X≤12)=e−12(5!125+6!126+7!127+8!128+9!129+10!1210+11!1211+12!1212)=0.5684.
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