Question #309837

Consider a population consisting of 1,2,3,4 and 5. Supposed samples of size 3 are drawn from this population. describe the sampling distribution of the sample means.


  • What is the mean and variance of the sampling distribution of the sample means?
1
Expert's answer
2022-03-15T17:36:17-0400

Population size N=5N=5

Sample size n=3n=3


Possible samples

=C53=(53)=10=C_5^3= \binom{5}{3}=10 samples


noSampleSamplemean11,2,32.021,2,42.3331,2,52.6741,3,42.6751,3,53.061,4,53.3372,3,43.082,3,53.3392,4,53.67103,4,54.0\def\arraystretch{1.5}\begin{array}{c:c:c}no &Sample& Sample mean\\\hline1&1,2,3&2.0\\\hdashline2&1,2,4&2.33\\\hdashline3&1,2,5&2.67\\\hdashline4&1,3,4&2.67\\\hdashline5&1,3,5&3.0\\\hdashline6&1,4,5&3.33\\\hdashline7&2,3,4&3.0\\\hdashline8&2,3,5&3.33\\\hdashline9&2,4,5&3.67\\\hdashline10&3,4,5&4.0\\\hline\end{array}



SamplemeanXiXˉ(XiXˉ)2(2.01.01.02.330.670.442.670.330.112.670.330.113.0003.330.330.113.0003.330.330.113.670.670.444.01.01.0\def\arraystretch{1.5}\begin{array}{c:c:c} Sample mean&X_i-\bar X&(X_i-\bar X)^2(\\\hline2.0&-1.0&1.0\\\hdashline2.33&-0.67&0.44\\\hdashline2.67&-0.33&0.11\\\hdashline2.67&-0.33&0.11\\\hdashline3.0&0&0\\\hdashline3.33&0.33&0.11\\\hdashline3.0&0&0\\\hdashline3.33&0.33&0.11\\\hdashline3.67&0.67&0.44\\\hdashline4.0&1.0&1.0\\\hline\end{array}


Mean μ=XiN=3010=3.0\mu=\dfrac{\sum X_i}{N}=\dfrac{30}{10}=3.0


Variance σ2=(XiXˉ)2N1\sigma^2=\dfrac{\sum(X_i-\bar X)^2}{N-1}


σ2=3.219=0.357\sigma^2 =\dfrac{3.21}{9}=0 .357


Sample means probability distribution






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