SInce 3 coins are tossed and on any of coins could occur both head and tail, then Y = {0, 1, 2, 3}. Since the probability of getting a tail is equal for every coin and equals to 0.5, then Y~BIN(3, 0.5)
P(Y=0)=(03)∗0.53=0.125
P(Y=1)=(13)∗0.53=0.375
P(Y=2)=(23)∗0.53=0.375
P(Y=3)=(33)∗0.53=0.125
