Answer to Question #309623 in Statistics and Probability for Whitney Gray

Question

The probabilities of a machine manufacturing 0, 1, 2, 3, 4, or 5 defective parts in one day are 0.75, 0.17, 0.04, 0.025, 0.01, and 0.005, respectively. Find the mean of the probability distribution.

Answer 1

we define the mean as below

mean = ( (0*0.75) + (1*0.17) + (2*0.04) + (3*0.025) + (4*0.01) + (5*0.005) )

=0.39