Question

5. What is the probability that a market inspector will discover, greater than five violations of the public health code?

Answer 1

Let the random variable $X$ represent the number of violations of the public health code.

The probability that a market inspector will discover greater than 5 violations of health code is

$$P(X\gt5)=1-P(X\le5)=1-P(X=0)$$

$$-P(X=1)-P(X=2)-P(X=3)$$

$$-P(X=4)-P(X=5)$$

$$=1-0.41-0.22-0.17-0.13-0.05-0.02$$

$$=0$$