5. What is the probability that a market inspector will discover, greater than five violations of the public health code?
Let the random variable "X" represent the number of violations of the public health code.
The probability that a market inspector will discover greater than 5 violations of health code is
"P(X\\gt5)=1-P(X\\le5)=1-P(X=0)""-P(X=1)-P(X=2)-P(X=3)"
"-P(X=4)-P(X=5)"
"=1-0.41-0.22-0.17-0.13-0.05-0.02"
"=0"
Comments
Leave a comment