Five hundred children participated in a field demonstration. Their heights averaged is 110 cm with a standard deviation of 6 cm. How many children belong to the upper 15% of the group?
Let X= height of a child: X∼N(μ,σ2).
Given μ=110 cm,σ=6 cm.
P(98<X<104)=P(X<104)−P(X≤98)
=P(Z<6104−110)−P(Z≤698−110)
=P(Z<−1)−P(Z≤−2)
≈0.158655−0.022750=0.135905
0.135905⋅500=68 68 children have heights between 98 cm and 104 cm.
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