As studied, the average number of hours spent by senior high school students for their online classes a week is 25 hours with a standard deviation of 4 hours. Assuming that study is true and the data is normally distributed.
Find the probability that a randomly selected senior high student spends more than 26 hours but less than 29 hours.
we use z scores
z(26) = (26 - 25)/ 4 = 0.25
z(29) = (29-25) /4 = 1
we define p(0.25<z<1), using the normal tables we obtain
(0.84134 - 0.59871) = 0.24263 which is the required solution.
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