Question

The average sale (no of burgers) of a fast food shop is 30 burgers/day. What is the

probability that exactly 50 burgers will be sold the next day? 

Answer 1

Let X : burger will be sold

$\therefore X \sim Poisson ( \lambda )$

$\lambda=30$ Per day

$P(X=x)=\frac{e^{-\lambda} {\lambda}^{x}}{x !}$

$P(X=x)=\frac{e^{-30}(30)^{x}}{x !}$

P( exactly 50 burgers will be sold the next day)

$\begin{aligned} \Rightarrow P(X=50) &=\frac{e^{-30}.{(30)^{50}}}{50 !} \\ &=0.00022 \\ &=0.0002 \end{aligned}$