Answer to Question #282491 in Statistics and Probability for seli

Question

If the uric acid values in normal adult males are approximately normally distributed with mean 4.7 mgs and standard deviation 1mg find the probability that a sample of size 9 will yield a mean.

Answer 1

Let $X=$ the sample mean: $X\sim N(\mu, \sigma^2/n).$

Given $\mu=4.7\ mg, \sigma=1\ mg, n=9.$

The probability that a sample of size 9 will yield a mean is

$$P(X=\mu)=P(X=4.7)=0$$