Question

If the uric acid values in normal adult males are approximately normally distributed with mean 4.7 mgs and standard deviation 1mg find the probability that a sample of size 9 will yield a mean.

Answer 1

Let $X=$ the sample mean: $X\sim N(\mu, \sigma^2/n).$

Given $\mu=4.7\ mg, \sigma=1\ mg, n=9.$

The probability that a sample of size 9 will yield a mean is

$$P(X=\mu)=P(X=4.7)=0$$