Question #281036

A set of 7 fair coins was tossed 259 times and the frequency of throws

observed were as follows:


Number of Heads : 0 1 2 3 4 5 6 7

Frequency of throws : 3 7 23 62 63 53 37 11


Fit a binomial distribution and find mean and standard deviation of fitted

distribution.


1
Expert's answer
2021-12-20T16:10:28-0500

mean:

μ=xifi/N=4.07\mu=\sum x_if_i/N=4.07


p=μ/n=4.07/7=0.58p=\mu/n=4.07/7=0.58

q=1p=0.42q=1-p=0.42


N=259N=259

n=7n=7

f(x=k)=NCnkpkqnkf(x=k)=NC^k_np^kq^{n-k}


f(x=0)=259q7=0.61f(x=0)=259q^{7}=0.6\approx1

f(x=1)=2597pq6=5.776f(x=1)=259\cdot7pq^{6}=5.77\approx6

f(x=2)=259C72p2q5=23.9124f(x=2)=259\cdot C^2_7p^2q^{5}=23.91\approx24

f(x=3)=259C73p3q4=55.0355f(x=3)=259\cdot C^3_7p^3q^{4}=55.03\approx55

f(x=4)=259C74p4q3=76f(x=4)=259\cdot C^4_7p^4q^{3}=76

f(x=5)=259C75p5q2=62.9763f(x=5)=259\cdot C^5_7p^5q^{2}=62.97\approx63

f(x=6)=2597p6q=28.9929f(x=6)=259\cdot7p^6q=28.99\approx29

f(x=7)=259p7=5.716f(x=7)=259p^7=5.71\approx6


for fitted data:

mean:

μ=xifi/N=4.05\mu=\sum x_if_i/N=4.05

standard deviation:

σ=fixi(fixi)2/NN=1.32\sigma=\sqrt{\frac{\sum f_ix_i-(\sum f_i x_i)^2/N}{N}}=1.32


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