Question #281034

For 10 observations on price (X) and supply (Y) the following data were

obtained (in appropriate units):

∑X = 130, ∑Y = 220, ∑X


2 = 2288, ∑Y


2 = 5506 and ∑XY = 3467.


Obtain the line of regression of Y on X and estimate the supply when the price is 16

units, and find out the standard error of the estimate.


1
Expert's answer
2021-12-23T17:56:36-0500

The line of regression of Y on X is expressed as:

Y=a+bXY=a+bX

Where;

b=nΣXY(ΣX)(ΣY)nΣX2(ΣX)2b=\frac{n\Sigma XY-(\Sigma X)(\Sigma Y)}{n \Sigma X^2-(\Sigma X)^2}


b=(10×3467)(130)(220)10(2288)2(130)2b=\frac{(10\times3467)-(130)(220)}{10 (2288)^2-(130)^2}

b=1.02b=1.02


a=ΣYbΣXna=\frac{\Sigma Y-b\Sigma X}{n}


a=2201.02×13010a=\frac{220-1.02\times130}{10}


a=8.74a=8.74


Y=8.74+1.02XY=8.74+1.02X


If the price (X) is 16 units then supply (Y) is:


Y=8.74+1.02×16Y=8.74+1.02\times16


Y=25.06Y=25.06


The standard error of the estimate is:


s=ΣY2aΣYbΣXYn2s=\sqrt{\frac{\Sigma Y^2-a\Sigma Y-b\Sigma XY}{n-2}}


s=5506(8.74×220)(1.02×3467)102s=\sqrt{\frac{5506-(8.74\times220)-(1.02\times3467)}{10-2}}


s=2.42s=2.42





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