for a random sample of 36 items and a sample mean of 211,compute a 95% confidence interval for if population standard deviation is 23
The z value is; 1.96
The interval will be calculated by the following formula;
"mean \\pm \\frac{z\u00d7sd}{\\sqrt{N}}"
"211 \\pm \\frac{1.96\u00d723}{\\sqrt{36}}"
Evaluating we get an interval of:
203.49 to 218.51
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