Answer to Question #264406 in Statistics and Probability for Madhu

Question #264406

A particular bulb has lifetimes of 1500 hours with a standard deviation of 6 hours. Find a range in which it can be guaranteed that 93.75% of the lifetimes of this brand of car lie.



(1489 and 1512)



(1482 and 1518)



(1476 and 1524)



(1470 and 1530)

1
Expert's answer
2021-11-12T12:29:44-0500

Mean = 1500

Standard deviation = 6

Z value at 93.75% confidence interval = 1.534


Mean±ZsnMean\pm Z \frac{s}{\sqrt{n}}


1500±1.534611500\pm 1.534 \frac{6}{\sqrt{1}}


1500±1.534×61500\pm 1.534 \times6


(1489 and 1512)



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