Leo a working student from STEM, rides a bicycle from house to school to save money. If the mean life of a tire is 10,000 km and the standard deviation is 200 km. 68% of all tires will have a life between how many kilometers?
Let X be a random variable representing the life of a tire. Then,
"X"~"N(\\mu,\\sigma^2)" where,
"\\mu=10,000"
"\\sigma^2=200^2=40,000"
Hence, "X"~"(10000, 40000)"
According to empirical rule, the area covered between mean minus 1 standard deviation and mean plus 1 standard deviation of a Normal distribution is 68%. This can be written as,
"p(\\mu-\\sigma\\lt X \\lt \\mu+\\sigma)=68\\%"
"p(10000-200 \\lt X \\lt 10000+200)=68\\%"
"p(9800 \\lt X \\lt 10200)=68\\%"
Therefore, "68\\%" of all tires will have a life between 9800km and 10200km.
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