The test scores of 40 students are summarized in the frequency distribution below. Find the standard deviation. Score Students 50-59 5 60-69 8 70-79 6 80-89 13 90-99 8
Mean "\\bar{X} = \\frac{\\sum f_iX_i}{N} = \\frac{3090}{40}=77.25"
Standard deviation "= \\sqrt{\\frac{\\sum f_iX_i^2}{N} - (\\bar{X})^2}"
"= \\sqrt{ \\frac{245700}{40} -(77.25)^2} \\\\\n\n= \\sqrt{6142.5 -5967.56} \\\\\n\n= \\sqrt{174.94} \\\\\n\n= 13.22"
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