Question

A fair spinner has 9 equal sections: 3 red, 2 blue and 4 green.

It is spun twice.

What is the probability of getting blue both times?

Answer 1

The probability of a blue section appearing every time is

$p = \frac{2}{{3 + 2 + 4}} = \frac{2}{9}$

Then the wanted probability is

$P = {p^2} = {\left( {\frac{2}{9}} \right)^2} = \frac{4}{{81}}$

Answer: $P = \frac{4}{{81}}$