Question #242702

 A random vector (X1, X2) is a discrete random vector if its space D or range space is finite or countable. Suppose X1, X2 are positive integer valued and we need to find P(X1= x1, X2= x2), where x1, x2 are known positive integers, in terms of their known cumulative distribution function F. 

1
Expert's answer
2022-01-31T16:14:44-0500

P(X1=x1,X2=x2)=P(X1=x1,X2x2)P(X1=x1,X2<x2)P(X_1= x_1, X_2= x_2)=P(X_1= x_1, X_2\leq x_2)-P(X_1= x_1, X_2< x_2)

=P(X1=x1,X2x2)P(X1=x1,X2x21)=P(X_1= x_1, X_2\leq x_2)-P(X_1= x_1, X_2\leq x_2-1)


P(X1=x1,X2x2)=P(X1x1,X2x2)P(X1<x1,X2x2)P(X_1= x_1, X_2\leq x_2)=P(X_1\leq x_1, X_2\leq x_2)-P(X_1< x_1, X_2\leq x_2)

=P(X1x1,X2x2)P(X1x11,X2x2)=P(X_1\leq x_1, X_2\leq x_2)-P(X_1\leq x_1-1, X_2\leq x_2)

=F(x1,x2)F(x11,x2)=F(x_1,x_2)-F(x_1-1,x_2)


Similarly, P(X1=x1,X2x21)=F(x1,x21)F(x11,x21)P(X_1= x_1, X_2\leq x_2-1)=F(x_1,x_2-1)-F(x_1-1,x_2-1).

Therefore,

P(X1=x1,X2=x2)=P(X_1= x_1, X_2= x_2)=

=(F(x1,x2)F(x11,x2))(F(x1,x21)F(x11,x21))=(F(x_1,x_2)-F(x_1-1,x_2))-(F(x_1,x_2-1)-F(x_1-1,x_2-1))

=F(x1,x2)F(x11,x2)F(x1,x21)+F(x11,x21)=F(x_1,x_2)-F(x_1-1,x_2)-F(x_1,x_2-1)+F(x_1-1,x_2-1)


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