μ=5σ=0.5P(X<5.5)=P(Z<5.5−5.00.5)=P(Z<1)=0.8413\mu = 5 \\ \sigma=0.5 \\ P(X<5.5) = P(Z< \frac{5.5-5.0}{0.5}) \\ = P(Z< 1) \\ = 0.8413μ=5σ=0.5P(X<5.5)=P(Z<0.55.5−5.0)=P(Z<1)=0.8413
(Using Z distribution table)
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