The life of an electronic device is known to have the exponential distribution with parameter λ = 1/1000 .
(i) What is the probability that the device lasts more than 1000 hours?
(ii) What is the probability it will last less than 1200 hours?
(iii) Find the mean and variance of the life of the electronic device.
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Expert's answer
2021-09-10T08:45:48-0400
Let X be the lifetime of the given electronic device. X has the exponential distribution with parameter λ=1/1000 means that P(X>t)=e−λt, for all t>0.
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