Sample space,S={1,2,3,4,5,6}
Let A be the event of getting an odd number.
Let B be the event of getting a prime number.
A={1,3,5},B={2,3,5},A∩B=3,5
The conditional probability of event B given that A has already occurred, P(B∣A)
=P(A)P(A∩B)=6362=32
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