"Sample \\space space,S=\\{1,2,3,4,5,6\\}\\\\"
Let A be the event of getting an odd number.
Let B be the event of getting a prime number.
"A=\\{1,3,5\\},B=\\{2,3,5\\},A\u2229B={3,5}"
The conditional probability of event B given that A has already occurred, P(B∣A)
"= \\frac{\n\nP(A\u2229B)}{P(A)}\n\u200b\n = \\frac{\\frac{2}{6}}{\\frac{3}{6}}=\\frac{2}{3}"
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