Answer to Question #233141 in Statistics and Probability for Neel

Question

Roll both a 10-sided fair die with an Ace side and a 12-sided fair die with an Ace side.

(a) What is the chance that one, and only one, of the dice will land Ace?  (Enter exact answer.)

(b) Given that one, and only one, of the dice landed Ace, what is the probability it was the 10-sided die?  (Enter exact answer.)

Answer 1

(a)

$$P(only\ one\ Ace)=\dfrac{1}{10}(\dfrac{11}{12})+\dfrac{9}{10}(\dfrac{1}{12})$$

$$=\dfrac{20}{120}=\dfrac{1}{6}$$

(b)

$$P(10-sided|only\ one\ Ace)$$

$$=\dfrac{P(only\ one\ Ace|10-sided)}{P(only\ one\ Ace)}$$

$$=\dfrac{\dfrac{1}{10}(\dfrac{11}{12})}{\dfrac{1}{6}}=\dfrac{11}{20}$$