Answer to Question #231938 in Statistics and Probability for Angie

Question

the sticker on nestle's crunch bar reads 20.4 grammes. Suppose that the probability distribution of the weight crunch bar is known to follow a normal distribution with variance of 0.16 and mean 21.37 grammes. Calculatethe probability that a weight of a crunch bar selected from the shelf will exceed 22.07 grammes

Answer 1

Solution:

$X\sim N(\mu,\sigma^2) \\\mu=21.37,\sigma^2=0.16$

$P(X>22.07)=1-P(X\le22.07) \\=1-P(z\le \dfrac{22.07-21.37}{\sqrt{0.16}}) \\=1-P(z\le1.75) \\=1-0.95994 \\=0.04006$