Question #231837

i need help with this second question two, theyre similar.


X represents the Grade Point Average (GPA) of students at a private college which follows normal distribution with mean of 2.8 and standard deviation of 0.52. If top 5% of the students will receive special awards, what is the minimum GPA required to qualify for the award?








1
Expert's answer
2021-09-02T12:35:20-0400

μ=2.8σ=0.52P(X<x)=10.05=0.95P(Z<x2.80.52)=0.95\mu=2.8 \\ \sigma=0.52 \\ P(X<x) = 1-0.05 = 0.95 \\ P(Z< \frac{x -2.8}{0.52}) = 0.95

From table of Z Score

x2.80.52=1.65x2.8=0.52×1.65x=2.8+0.858x=3.658\frac{x -2.8}{0.52} = 1.65 \\ x -2.8 = 0.52 \times 1.65 \\ x = 2.8 + 0.858 \\ x = 3.658

Answer: The minimum GPA required to qualify for the award is 3.66.


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