Let X= the number of admitted students: X∼Bin(n,p).
Given p=0.6,n=10,q=1−p=0.4.
(i)
P(X≤5)=P(X=0)+P(X=1)+P(X=2)
+P(X=3)+P(X=4)+P(X=5)
=(010)(0.6)0(0.4)10−0+(110)(0.6)1(0.4)10−1
+(210)(0.6)2(0.4)10−2+(310)(0.6)3(0.4)10−3
+(410)(0.6)4(0.4)10−4+(510)(0.6)5(0.4)10−5
≈0.3667
(ii)
P(X≤3)=P(X=0)+P(X=1)+P(X=2)
+P(X=3)=(010)(0.6)0(0.4)10−0
+(110)(0.6)1(0.4)10−1+(210)(0.6)2(0.4)10−2
+(310)(0.6)3(0.4)10−3≈0.0548
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