The probability that a student is admitted to MCBS for bachelor is 0.6. If 10 students from the same school apply, find the probability that (i) at most 5 are admitted. (ii) at least 7 are rejected
Let "X=" the number of admitted students: "X\\sim Bin(n, p)."
Given "p=0.6, n=10, q=1-p=0.4."
(i)
"+P(X=3)+P(X=4)+P(X=5)"
"=\\dbinom{10}{0}(0.6)^0(0.4)^{10-0}+\\dbinom{10}{1}(0.6)^1(0.4)^{10-1}"
"+\\dbinom{10}{2}(0.6)^2(0.4)^{10-2}+\\dbinom{10}{3}(0.6)^3(0.4)^{10-3}"
"+\\dbinom{10}{4}(0.6)^4(0.4)^{10-4}+\\dbinom{10}{5}(0.6)^5(0.4)^{10-5}"
"\\approx0.3667"
(ii)
"+P(X=3)=\\dbinom{10}{0}(0.6)^0(0.4)^{10-0}"
"+\\dbinom{10}{1}(0.6)^1(0.4)^{10-1}+\\dbinom{10}{2}(0.6)^2(0.4)^{10-2}"
"+\\dbinom{10}{3}(0.6)^3(0.4)^{10-3}\\approx0.0548"
Comments
Leave a comment