“Each average has its own special features and it is difficult to say which one is the best”.
explain this statement.
4(b) The mean age of the combined group of men and women is 30.5 years. If the mean age of
the sub-group of men is 35 years and that of the sub-group of women is 25 years, find out
percentage of men and women in the group.
4(c) The mean and median of a moderately skewed distribution are 42.2 and 41.9 respectively.
Find mode of the distributio
Part a
In layman's terms, an average is a single number chosen to represent a set of data. Different definitions of average are employed in various situations. The term "average" is frequently used to refer to the mathematical mean, which is the total of the numbers divided by the number of numbers averaged. In statistics, the mean, median, and mode are all regarded as measures of central tendency, and in common parlance, any of these might be referred to as an average number.
Part b
"30.5=\\frac{35\\mu+25(100-\\mu)}{100}\\\\\n3050=35\\mu+2500-25\\mu\\\\\n3050-2500=35\\mu-25\\mu\\\\\n550=10\\mu= 55\\\\\nNo.\\space of\\space men =55\\\\\nNo.\\space of\\space women=100-\\mu=100-55=45\\\\"
"Percentage\\space of\\space men= 55\\%\\\\\nPercentage\\space of\\space women= 45\\%"
Part c
Given :
Formula Used :
Step-by-step explanation :
It is Given that,
Mean = 42.2
Median = 41.9
Mode =?
As We know that,
Mode = 3 × median - 2 × mean
Substituting the values in the above formula, we get,
"= 3 \u00d7 41.9 - 2 \u00d7 42.2\\\\\n\n= 125.7 - 84.4\\\\\n\n= 41.3"
Therefore, Distribution of the mode = 41.3
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