If we were given mean as 40 and standard deviation as 2 and asked the proportion of shirts manufactured in each category, the following solution will apply
Small
0<X<37
Since μ=40 and σ=2
=P(0<X<37)=P(0−40<X−μ<37−40)=P(20−40<σX−μ<237−40)=P(−20<Z<−1.5)=0.0668⟹Psmall=0.0668∗100=7%
Medium
37<X<40.5
Since μ=40 and σ=2
=P(37<X<40.5)=P(37−40<X−μ<40.5−40)=P(237−40<σX−μ<240.5−40)=P(−1.5<Z<0.25)=0.5319⟹Pmedium=0.5319∗100=53%
Large
40.5<X<44
Since μ=40 and σ=2
=P(40.5<X<44)=P(40.5−40<X−μ<44−40)=P(240.5−40<σX−μ<244−40)=P(0.25<Z<2)=0.3785⟹Plarge=0.3785∗100=38%
Extra-Large
X>44
Since μ=40 and σ=2
=P(X>44)=P(X−μ>44−40)=P(σX−μ>244−40)=P(Z>2)=0.0228⟹Pextra−large=0.0228∗100=2%
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