Answer to Question #228135 in Statistics and Probability for chisenga

Question #228135
Sports shirts are frequently classified as S, M, L, XL for small, medium, large
and extra-large neck sizes. S fits a neck circumference of less than 37cm, M
fits between 37 and 40.5cm and L fits between 40.5cm and 44cm while XL fits
necks over 44cm in circumference. The neck circumference of adult males has
a normal distribution with
1
Expert's answer
2021-08-24T06:52:09-0400

If we were given mean as 40 and standard deviation as 2 and asked the proportion of shirts manufactured in each category, the following solution will apply

Small

0<X<370<X<37

Since μ=40\mu = 40 and σ=2\sigma = 2

=P(0<X<37)=P(040<Xμ<3740)=P(0402<Xμσ<37402)=P(20<Z<1.5)=0.0668    Psmall=0.0668100=7%= P(0<X<37)\\ = P(0-40<X-\mu<37-40)\\ = P(\frac{0-40}{2}<\frac{X-\mu}{\sigma}<\frac{37-40}{2})\\ = P(-20<Z<-1.5)\\ =0.0668\\ \implies P_{small}= 0.0668*100=7 \%


Medium

37<X<40.537<X<40.5

Since μ=40\mu = 40 and σ=2\sigma = 2

=P(37<X<40.5)=P(3740<Xμ<40.540)=P(37402<Xμσ<40.5402)=P(1.5<Z<0.25)=0.5319    Pmedium=0.5319100=53%= P(37<X<40.5)\\ = P(37-40<X-\mu<40.5-40)\\ = P(\frac{37-40}{2}<\frac{X-\mu}{\sigma}<\frac{40.5-40}{2})\\ = P(-1.5<Z<0.25)\\ =0.5319\\ \implies P_{medium}= 0.5319*100=53 \%


Large

40.5<X<4440.5<X<44

Since μ=40\mu = 40 and σ=2\sigma = 2

=P(40.5<X<44)=P(40.540<Xμ<4440)=P(40.5402<Xμσ<44402)=P(0.25<Z<2)=0.3785    Plarge=0.3785100=38%= P(40.5<X<44)\\ = P(40.5-40<X-\mu<44-40)\\ = P(\frac{40.5-40}{2}<\frac{X-\mu}{\sigma}<\frac{44-40}{2})\\ = P(0.25<Z<2)\\ =0.3785\\ \implies P_{large}= 0.3785*100=38 \%


Extra-Large

X>44X>44

Since μ=40\mu = 40 and σ=2\sigma = 2

=P(X>44)=P(Xμ>4440)=P(Xμσ>44402)=P(Z>2)=0.0228    Pextralarge=0.0228100=2%= P(X>44)\\ = P(X-\mu>44-40)\\ = P(\frac{X-\mu}{\sigma}>\frac{44-40}{2})\\ = P(Z>2)\\ =0.0228\\ \implies P_{extra-large}= 0.0228*100=2 \%

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