Topic: Normal Distribution Distribution & Inverse Normal Distribution
1.) The value of P( -1.96 < Z < 1.96 ) is .
A. 0.9000
B. 0.9500
C. 0.9900
D. 0.9990
2.) The area under a normal curve between 0 and -1.75 is __________.
A. 0.0401
B. 0.9599
C. 0.4599
D. None of the above
1.
where Z ~ N(0, 1).
This is equal to P(Z < 1.96) - P(Z < -1.96)
= F(1.96) - F(-1.96) = F(1.96) - (1 - F(1.96)) = 2 F(1.96) - 1
Now we need to look in a table to find out what F(1.96) is.
If you look in statistical tables for the standard normal distribution,
To find F(1.96), read across the 1.9 line until you get to 6 (for 1.96). So F(1.96) = 0.975 .
Hence P(-1.96 < Z < 1.96) = 2 × 0.975 - 1 = 0.95 .
2.
P(-1.75<z<0)
= P(0<z<1.75)
= 0.4599
Comments
Leave a comment