"S=\\{e_1,e_2,e_3,e_4\\}"
Given,
"P(e_2)=1\/5\\\\P(e_3)=1\/3"
and we know that
"P(e_1)+P(e_2)+P(e_3)+P(e_4)=1\\\\\\ \\\\\\implies P(e_1)+\\dfrac{1}{5}+\\dfrac{1}{3}+P(e_4)=1\\\\\\ \\\\\\implies P(e_1)+P(e_4)=1-\\dfrac{1}{5}-\\dfrac{1}{3}=\\dfrac{7}{15}"
Let "P(e_4)=\\dfrac{1}{15}"
So, "P(e_1)=\\dfrac{7}{15}-\\dfrac{1}{15}=\\dfrac{6}{15}"
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