"\\bar{x}=16.8 \\\\\n\n\\sigma = \\sqrt{16}=4 \\\\\n\nn=60"
A. The point estimate for \mu is the mean age for grade 11 students included in the sample of 60 students. In this case, the mean age of grade 11 students included in the sample is 16.8 years. The point estimate for \mu is 16.8 years.
B. Two-sided confidence interval:
"CI = (\\bar{x} - \\frac{Z_c \\times \\sigma}{\\sqrt{n}}, \\bar{x} + \\frac{Z_c \\times \\sigma}{\\sqrt{n}}) \\\\\n\nCI = (16.8 - \\frac{1.96 \\times 4}{\\sqrt{60}}, 16.8 + \\frac{1.96 \\times 4}{\\sqrt{60}}) \\\\\n\nCI = (16.8 -1.01, 16.8 + 1.01) \\\\\n\nCI = (15.79, 17.81)"
C. (15.79, 17.81) is a range of values (upper and lower) that you can be 95% certain contains the true mean of the population.
Comments
Leave a comment