If x is a standard normal variate find the following probabilities by using normal probability i) p(0.87<x<1.28)
ii) p(-0.34<x<0.62)
iii) p(x>0 85)
iv)p(x>-0.65)
i)
"P(0.87<x<1.28)=P(x<1.28)-P(x\\leq 0.87)""\\approx0.8997274-0.8078498\\approx0.091878"
ii)
"P(-0.34<x<0.62)=P(x<0.62)-P(x\\leq -0.34)""\\approx0.7323711-0.3669283\\approx0.365443"
iii)
"P(x>0.85)=1-P(x\\leq 0.85)""\\approx0.197663"
iv)
"P(x>-0.65)=1-P(x\\leq -0.65)""\\approx0.742154"
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