Question #213862

Experience has shown that a certain lie detector will show a positive reading (indicates a lie) 10% of the time when a person is telling the truth and 95% of the time when a person is lying. Suppose that a random sample of 5 suspects is subjected to a lie detector test regarding a recent one-person crime. Find the probability of observing no positive reading if all suspects plead innocent and are telling the truth.


1
Expert's answer
2021-07-06T10:20:13-0400

P(Test  negativeTruth)=1P(Test  positiveTruth)=10.10=0.90P(all  five  results  are  test  negativeAll  suspects  telling  truth)==p5=0.95=0.591P(\frac{Test \;negative}{Truth}) = 1 -P(\frac{Test \;positive}{Truth}) \\ = 1 -0.10 \\ = 0.90 \\ P(\frac{all\;five\;results\;are\;test\;negative}{All\;suspects \;telling\;truth}) = \\ = p^5 \\ = 0.9^5 \\ = 0.591


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS