Question #213453

8.A coin is loaded so that heads is three times as likely as the tails. For 3 independent tosses of the coin find the pmf of the total number of heads realised and the probability of realizing at most 2 heads.

9.Supposse that the random variable x has a p.d.f given by f(x)={cx,0<x<1 o ,elsewhere.Find the values of the constant c hence determine m. so that p(x<or equal to m)=1/2


1
Expert's answer
2021-07-13T05:08:48-0400

8. Let X=X= the number of heads realised: XBin(n,p)X\sim Bin(n, p)

Given n=3,p=0.75,q=0.25n=3, p=0.75, q=0.25


P(X=x)=(3x)(0.75)x(0.25)3x,x=0,1,2,3P(X=x)=\dbinom{3}{x}(0.75)^x(0.25)^{3-x}, x=0,1,2,3

x0123p(x)1/649/6427/6427/64\def\arraystretch{1.5} \begin{array}{c:c} x & 0 & 1 & 2 & 3 \\ \hline p(x) & 1/64 & 9/64 & 27/64 & 27/64 \\ \end{array}

P(X2)=1P(X=3)=12764=3764P(X\leq2)=1-P(X=3)=1-\dfrac{27}{64}=\dfrac{37}{64}

=0.578125=0.578125


9.


f(x)dx=01cxdx\displaystyle\int_{-\infin}^{\infin}f(x)dx=\displaystyle\int_{0}^{1}cxdx

=c[x22]10=c2=1=>c=2=c\big[\dfrac{x^2}{2}\big]\begin{matrix} 1 \\ 0 \end{matrix}=\dfrac{c}{2}=1=>c=2

0m2xdx=12,0<m<1\displaystyle\int_{0}^{m}2xdx=\dfrac{1}{2}, 0<m<1

[x2]m0=12[x^2]\begin{matrix} m \\ 0 \end{matrix}=\dfrac{1}{2}

m2=12m^2=\dfrac{1}{2}

Since 0<m<1,0<m<1, we take m=22.m=\dfrac{\sqrt{2}}{2}.



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