"\\displaystyle\\sum_{y=0}^{\\infin}p(y)=\\displaystyle\\sum_{y=0}^{\\infin}c(\\dfrac{3}{4})^y=\\dfrac{c}{1-\\dfrac{3}{4}}=4c=1"
"c=\\dfrac{1}{4}"
"=\\dfrac{1}{4}(\\dfrac{3}{4})^0+\\dfrac{1}{4}(\\dfrac{3}{4})^1+\\dfrac{1}{4}(\\dfrac{3}{4})^2=\\dfrac{37}{64}"
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