Question #213446
  1. A discrete random variable Y has a pmf given by p(Y=y)=c(3/4)X for y=0,1,2,....Find the values of the constant c and p(x<3)
1
Expert's answer
2021-07-11T09:04:49-0400
p(Y=y)=c(34)y,y=0,1,2,...p(Y=y)=c(\dfrac{3}{4})^y, y=0,1,2,...

y=0p(y)=y=0c(34)y=c134=4c=1\displaystyle\sum_{y=0}^{\infin}p(y)=\displaystyle\sum_{y=0}^{\infin}c(\dfrac{3}{4})^y=\dfrac{c}{1-\dfrac{3}{4}}=4c=1

c=14c=\dfrac{1}{4}


p(Y<3)=P(Y=0)+P(Y=1)+P(Y=2)p(Y<3)=P(Y=0)+P(Y=1)+P(Y=2)

=14(34)0+14(34)1+14(34)2=3764=\dfrac{1}{4}(\dfrac{3}{4})^0+\dfrac{1}{4}(\dfrac{3}{4})^1+\dfrac{1}{4}(\dfrac{3}{4})^2=\dfrac{37}{64}



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