Answer to Question #205140 in Statistics and Probability for Shema Derrick

Question #205140

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue? 


1
Expert's answer
2021-06-14T15:25:04-0400

The total number of balls is


2+3+2=72+3+2=7


The number of balls which are not blue is 2+3=5.2+3=5.

The probability that the first ball is not blue and the second ball is bot blue is


P(BB)=57(5171)=1021P(B'B')=\dfrac{5}{7}(\dfrac{5-1}{7-1})=\dfrac{10}{21}

The probability that none of the balls drawn is blue is 1021\dfrac{10}{21} .



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