A school survey found that 9 out of 10 students like pizza. If three students are chosen at random with replacement, what is the probability that all the three students like pizza?
Binomial distribution
"P=\\frac{9}{10}=0.9"
"n=3"
"P(x)=\\binom{n}{x}p^x(1-p)^{n-x}, x=0,1,2,3"
"P(3)=\\binom{3}{3}0.9^3=0.729"
Comments
Leave a comment