A school survey found that 9 out of 10 students like pizza. If three students are chosen at random with replacement, what is the probability that all the three students like pizza?
Binomial distribution
P=910=0.9P=\frac{9}{10}=0.9P=109=0.9
n=3n=3n=3
P(x)=(nx)px(1−p)n−x,x=0,1,2,3P(x)=\binom{n}{x}p^x(1-p)^{n-x}, x=0,1,2,3P(x)=(xn)px(1−p)n−x,x=0,1,2,3
P(3)=(33)0.93=0.729P(3)=\binom{3}{3}0.9^3=0.729P(3)=(33)0.93=0.729
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